this is pretty easy probably, but i cant seem to get the right answer .?

Question

x'3 - x'2 -4x + 4 divided by x'2 - x -6.

thank you. with x'3 i mean x cubed and so on.

Answer 1

Firstly, good idea about the exponents, that way looks a lot better than using ^.
Alright, whenever you use polynomials, the first thing to do is factorize. The denominator becomes (x-3)(x+2). It's fairly easy to divide the numerator by x+2, which leaves you with;
x'2-3x+2
------------
x-3
You'll have to fill in your own working (I just do those in my head), and you might want to try simplifying that further.

EDIT: oh, yeah... I forgot about long-division.

Answer 2

Denominator = x² - x - 6 = (x + 2).(x - 3)
(x³ - x² - 4x + 4) / (x + 2)(x + 3)
= (x² - 3x + 2) / (x + 3)----(after dividing by (x + 2)
= (x - 2)(x - 1) / (x + 3)

Answer 3

Wow. I haven't done this stuff since 10th grade. I think the answer is negative x cubed over 6. I could be very wrong, but I tried. Good luck!

Answer 4

x
x2 - x - 6 I x3 - x2 - 4x + 4
-x3 + x2 + 6x
= 2x + 4

the answer is x remainder 2x +4.

Answer 5

x^3-x^2-4x+4
=x^2(x-1)-4(x-1)
=(x-1)(x^2-4)
=(x-1)(x+2)(x-2)
x^2-x-6
=x^2-3x+2x-6
=X(x-3)+2(x-3)
=(x+2)(x-3)
therefore given expression
=(x-1)(x+2)(x-2)/(x+2)(x-3)
=(x-1)(x-2)/(x-3)

Answer 6

x remainder 2x+4