How many grams of copper(II) nitrate could be formed from the reaction of 2.077 g of copper with excess HNO3?

Question

i asked a similar quesiton to this....i tried solving it on my own but im not sure if its right
i got 6.130 as the answer.

Answer 1

Cu + 2 HNO3 ---> Cu (NO3)2 +H2

in molecular mass
Cu = 63.5 Cu (NO3)2 = 63.5 +(14+3*16)2+187.5

So 63.5 g of Cu correspond to 187.5g of Cu (NO3)


and 2.077 Cu --> (187.5/63.5)*2.077=6.13g Correct