What is centripetal force?

Question

Ok, i was told that if i was to spin a rope attached with a ball at the end around myself, the Centripetal Force is the resultant vector of Tension and Fg.
Is that true?
And if so, is the Centripetal Force always parallel to the horizontal ground?

i understand you guys, but the more i read, the more i think the text book answer i got is wrong. which is what really confusing me.

Q. a ball of mass 0.05kg was whirled in a horizontal circle of radius 1m at 0.8 secs per lap. and the ball makes a 30 degrees angle with the horizontal. where 'a' is.
l\
l \
l \
l \
l __a\
O

correct data according to the book:
v = 7.85m/s
centripetal acceleration = 61.68m/s/s
*centripetal force = 3.08N
*Tension of wire = 3.56N

if my comprehension serves me right (which may not), Tension should be smaller then the Centripetal Force, because CF is a resultant vector of Tension and Fg(mg).

Answer 1

It can be vertical as well. The only thing that makes vertical centripetal force problems harder is that another force is involve: mg. So, the centripetal force that points toward the center of a vertical loop counteracts gravity at each point of the loop. BTW the spinning-the-rope thing: don't assume that the c-force is parallel. There is mg acting on it as well, which does give it a slightly downward angle.

Answer 2

Centripetal Force is a centre-seeking force that causes an object to move in a circular path. When a ball is tied to a string and swung around in a circle at a constant velocity. The ball moves in a circular path because the string applies a centripetal force to the ball. According to Isaac Newton's first law of motion, a moving object will travel in a straight path unless acted on by a force (see Mechanics). If the string were suddenly cut, the ball would no longer be subject to the centripetal force and would travel in a straight line in a direction tangent to the circular path of the ball (if not for the force of gravity).
The centripetal force is only parallel to the ground when the motion is parallel.

Answer 3

Centripetal force is the external force required to make a body follow a circular path at constant speed.

So the tension in the rope is the force holding the ball in a circular path. If the tension exceeds the strength of the rope, the ball will fly off in a straight line tangent to the circular motion.

The force is directed inward, toward the center of the circle. Thus, the force will only be parallel to the ground when the motion is parallel too.

Answer 4

You can't really argue with it, but I've always stated it slightly differently.

In my model of the situation, with the ball travelling in a horizontal circular path, I'd say the Tension force in the rope can be resolved into two components.

A vertical component providing a reaction to the gravitational weight force and a horizontal component, towards the centre, providing the centripetal force necessary to keep the ball travelling in a horizontal circular path.

Either way you end up slightly dizzy, but with the same answer.

Answer 5

The Centripetal force is the force pulling inwards against an equal force pulling outwards (known as the Centrifugal force).

The centripetal force maintains the outward pulling force in a circular path.

Should the centripetal force fail, the objects' circular path will be broken and the object will fly off in a straight trajectory at a tangent to the original circular path.

It is not necessarily parallel to the horizontal.

Answer 6

In layman's terms, the centripetal force is what stops the centrifugal force from making whatever you're spinning flying away. (Two forces cancelling each other out.)
In your example, the force of you pulling the string is the centripetal force. (Or maybe the tension in the string, that's a bit of a technicality.)

The centripetal force is only parallel to the ground if you're spinning it parrallel to the ground. In something like the propeller on a plane, the centripetal force is perpendicular to the ground, coz that's the way it's spinning.

Answer 7

First i ought to remark that your formulation isn't valid. F = (m* V * V )/R there is not any "g" in the equation itself. in F = m a, F is the resultant rigidity. it really is robotically used. there should be many utilized forces yet when an merchandise speeds up then all of us be conscious of the resultant of all of them practice. in addition in a circle. If it strikes in a circle then F = m a ( as a vector) and F = m v^2 /r properly shows the resultant rigidity mandatory to reason this action. no count number what number individual forces that are utilized all of us be conscious of the powerful effect of all of them practice. The time period for this resultant rigidity is centripetal rigidity. it really is fairly genuine. And the time period should be used because it properly describes the placement. even if the terminology isn't continuously used precisely. when it comes to the airplane, the full of all different forces will equivalent centripetal rigidity if the airplane is transferring in a circle with consistent %. It "balances" in person-friendly words in the way that the left hand area of any "equals signal" balances the right hand . area. when it comes to letting the ball flow, you get rid of the rigidity of the string so that you at the instantaneous are no longer forcing the ball to flow in a circle. for this reason the ball could flow in a promptly line at consistent %. it really is the equivalent of preventing pushing something. It maintains in a promptly line at consistent % in simple terms as your ball does once you end pulling it. ( See Newtons guidelines). Centrifugal rigidity is a rigidity that appears to be like present day. it form of feels as if an merchandise is pulling outwards. it should be considered that it really is unfaithful. If an merchandise is fairly attempting to flow outwards ( a tremendous charge being repelled with assistance from a nucleus as an party) then it speeds up promptly outwards once the different forces are bumped off. this isn't the case for the ball So centrifugal rigidity isn't suitable in spite of if there should be situations the position it really is a sensible fiction..

Answer 8

Centrifugal force (from Latin centrum "center" and fugere "to flee") is a term which may refer to two different forces which are related to rotation. Both of them are oriented away from the axis of rotation, but the object on which they are exerted differs.

A real or "reactive" centrifugal force occurs in reaction to a centripetal acceleration acting on a mass. This centrifugal force is equal in magnitude to the centripetal force, directed away from the center of rotation, and is exerted by the rotating object upon the object which imposes the centripetal acceleration. Although this sense was used by Isaac Newton,[1] it is only occasionally used in modern discussions.[2][3][4][5]
A pseudo or "fictitious" centrifugal force appears when a rotating reference frame is used for analysis. The (true) frame acceleration is substituted by a (fictitious) centrifugal force that is exerted on all objects, and directed away from the axis of rotation.