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The specific heat of lead metal is .127 J/g *C. How many joules of heat would be required to raise the temperature of a 5.00g sample from 25*C to 35*C?

Can somebody please help me with this?

2007-03-18 21:52:24 · 2 answers · asked by keenan93312 1 in Science & Mathematics ➔ Chemistry

2 answers

the formula is Q= m c (tf-ti)

where m = mass here 5g

c specific heat = 127 J/g *C

tf = 35 ti = 25 tf-ti =10

So q = 5*10*127 = 6350J

2007-03-18 23:25:52 · answer #1 · answered by maussy 7 · 0⤊ 0⤋

Multiply the specific heat by number of grams by temperature change.

0.127 x 5 x 10 = 6.35 J

2007-03-19 06:40:31 · answer #2 · answered by Norrie 7 · 0⤊ 0⤋