Please see question below?

0 ⤊

Please see question below?

The molar heat of vaporization of ethyl acetate, (CH3COOCH2CH3) is 32.5 KJ/mol. How much energy is required to vaporize 2.57 g of ethyl acetate?

I came up with 1113.0 KJ/mol, but I know that it's not right. Can someone please help me?

2007-03-18 20:45:30 · 2 answers · asked by keenan93312 1 in Science & Mathematics ➔ Chemistry

2 answers

there is 96 g/mol of ethyl acetate, according to my calculations. divide the given grams by the g/mol, and multiply that number times the number of kj/mol. my answer is 0.870 kj!

not 100%, i'm a little rusty on this, but i think it's right.

2007-03-18 20:56:42 · answer #1 · answered by wookin pa nub 6 · 0⤊ 0⤋

Molar mass of Ethyl acetate is

(12+3+44+29) g = 88 g

Thus Heat of vap is 2.57*32.5/88 kJ = 0.949 kJ

2007-03-19 03:58:49 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋