how many moles are in 0.44g of nitric acid?

0 ⤊

how many moles are in 0.44g of nitric acid?

2007-03-18 19:54:42 · 4 answers · asked by kevin 1 in Science & Mathematics ➔ Chemistry

4 answers

Nitric acid is HNO3
M(HNO3)=1+14+16*3=63
Moles(HNO3)=mass(HNO3)/M(HNO3)
=0.44/63
=7*(10^-3)
=0.007

2007-03-18 20:23:53 · answer #1 · answered by beuuu 2 · 0⤊ 0⤋

the answers above are true if the purity of nitric acid is 100%, i mean there is no water in it, the condition that is not easily achievable. so you should know the purity level of that and multiple the above answers to it

2007-03-19 05:00:40 · answer #2 · answered by corr man 1 · 0⤊ 0⤋

0.44 / (1 + 14 + 3*16)

2007-03-19 03:02:32 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋

.0069 moles

2007-03-19 03:12:57 · answer #4 · answered by ravi k 1 · 0⤊ 0⤋