how many atoms are there in 0.98 moles of iron?

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2007-03-18 19:38:34 · 5 answers · asked by Kevin 1 in Science & Mathematics ➔ Chemistry

.98moles X 6.02 X 10^23 atoms/mole = 5.90 X 10^23 atoms

2007-03-18 19:48:43 · answer #1 · answered by Anonymous · 0⤊ 0⤋

We know there are 6.022 x 10^(23) atoms of anything in a mole. So you just need to multiply 0.98 x 6.022 x 10^(23) to get the atoms in .98 moles.

2007-03-19 02:41:51 · answer #2 · answered by chinkyshinhwaluv 3 · 0⤊ 0⤋

6.022*10^23 * 0.98 = 5.90156*10^23 atoms!

2007-03-19 02:51:43 · answer #3 · answered by new_einstein 2 · 0⤊ 0⤋

1 mole of iron contains 6.023* 10^23 atoms, so .98 will contain...

2007-03-19 02:42:17 · answer #4 · answered by s_kundu88 3 · 0⤊ 0⤋

4 for each 8th of a mole you figure it out

2007-03-19 02:41:42 · answer #5 · answered by nightchild35 2 · 0⤊ 1⤋