How do you use the information you have for the equivalence point from a titration curve (pH vs. volume of NaOH added -the titrant) to calculate the unknown concentraton of NaOH?
You have the initial concentration of the acetic acid, as well as the volume. How do you determine the concentration of the NaOH used, from the equivalence point data which is a pH of 8.32 and a volume of NaOH of 25.19? Please Help!!
2007-03-18 16:33:25 · 2 answers · asked by Belle 3 in Science & Mathematics ➔ Chemistry
Assume that the endpoint of the reaction is neutralization of the following reaction:
HOAc (aq) + NaOH (aq) --> NaOAc (aq) + H2O (l)
Va*Ca = Vb*Cb or Cb = (Va*Ca)/Vb
Cb (the concentration of the base - NaOH) =
Va (vol of acid) * Ca (conc. of acid) / Vb (conc. of base)
2007-03-19 00:59:23 · answer #1 · answered by Richard 7 · 10⤊ 0⤋
A molar answer means moles/Liter. You used 22ml of a nil.5M sol'n. that should be 11 miliMoles of NaOH (22*0.5). for each H+ it takes one OH-. yet you don't be conscious of what the acid is. it will be HCl. meaning there have been 11 milimoles of the acid. so that you had 11 milimoles in 30 mL. The concentration of the acid replaced right into a touch over 0.33M. (no calculator accessible). even if the acid ought to were H2SO4 (2 H+). in which case the most concentration ought to 0.5 or about 0.33/2 M. you may draw close what the acid is. Then stability the acid/base rxn. this may allow you to be conscious of how many moles of the bottom are used in step with mole of the acid.
2016-11-26 21:41:25 · answer #2 · answered by ? 4 · 0⤊ 0⤋