I dont know how to do it, I found -2 as a zero and -2+-2√6 but there is still supposed to be one positive root and i dont know what it is =(
2007-03-18 15:23:13 · 3 answers · asked by PPan 2 in Education & Reference ➔ Homework Help
what about the imaginary? are there supposed to be two?
2007-03-18 15:32:25 · update #1
Hi, it seems like you have already found all the roots. In a cubic polynomial there are 3 roots.
In this case you have found -2, -2+2√6 (this is the positive number you were looking for), and -2-2√6
Therefore these three are the three correct roots.
2007-03-18 15:43:05 · answer #1 · answered by Michael784 2 · 0⤊ 0⤋
also, just plug the equation into ur t83+ or higher and you can hit second and graph and look where y=0 and the corresponding value will be a zero.
once you do that you can do synthetic division to factor out that 2 and than simply use the quadratic formula to get the 2+-(rad 6) **i dont know how u got the radical signbut good work)
that may sound confusing but it is the easiest way to get the answer as oppsed to factoring it.
2007-03-18 22:45:40 · answer #2 · answered by cassandracorrao 3 · 0⤊ 0⤋
-2 + 2 sqrt(6) is positive
it is a 3rd degree polynomial so it can only have 3 roots
2007-03-18 22:29:19 · answer #3 · answered by ... 3 · 1⤊ 0⤋