3 math questions i need help with?

Question

1.) how do you find the volume of a sphere?

2.) The ratio of the three sides of triangle ABC are 5:4:3 and the perimeter is 360 meters. explain how and find the three side lengths.

3.) The paw print of the OU bobcats is shown on a postcard that is 3.5 by 5 inches. Suppose the card image is enlarged so that the ratio of the original to the enlargement is 3:4. Then the bigger print was enlarged so that the ratio of the first enlargement to the second is 2:3. Find the dimension s of both enlargements.

Please show work for the last 2 as well...

thanks

On number two also find the lengths of the sides

Answer 1

1. (4/3)*Pi*r^3
2. a very common and basic triangle is referred as the three-four-five triangle because of the simple pythag:

5^2 = 4^2 + 3^2
25 = 16 + 9
very easy numbers to deal with
so a simple method to find a perimeter of 360m is to multiply all sides by increasing values until you reach 360
so starting with the value of 20 u have
100:80:60 .......100+80+60=240
30->
150:120:90........150+120+90=360
guess n check is a good method if the values are simple enough

if u dont wanna use guess n check then an alternative method is this:
simplify the ratio to fractions and making one of the ratios equal to one....like so:
1:4/5:3/5
let X be the hypotneuse of the 360m perimeter triangle

X + 4/5X + 3/5X = 360
5/5X + 4/5X + 3/5X = 360
12/5X = 360
X=150
150m is the length of ur hypotneuse...to find the other sides plug X into 4/5X and 3/5X

3. take the values of the dimensions and divide by 3 then multiply by 4....with those new values it becomes enlarged again so divide by 2 and multiply by 3 to find the set of enlarged dimensions....
quick and ez explanation is lets say i have a 2 cm line and i enlarge it with 3:4.......since its becoming bigger, the value should be bigger as well so...
2/3 = 0.66 x 4 = 2.64
so my new enlarged line is 2.64 cm

Answer 2

1 im pretty sure is 4/3TTr^2 ( not sure)

2 add up the ratios to 12
360/12
30 for each 1 in the ratio

thus
side A (3) = 90
side B (4) = 120
side C (5) = 150


3 i have no idea, sorry but 1 and 2 are right #2 is def right.. tell me how to do 3 if and when u figure it out

Answer 3

1.)V= 4/3 (pi) (radius^3)

2.) Label the three sides of the triangle 5x, 4x, and 3x. then you know the perimeter so set the sides equal to the perimeter:
5x + 4x + 3x = 360
12x = 360
x = 30
Now, substitute 30 for x and you get that the sides of the triangle are 150, 120, and 90.

Hope this helps!

Answer 4

dude im not doing ur hw

Answer 5

do ur own homework