Help with a program not running correctly?

Question

For some reason it takes the string but does not show any result for the string can anybody help?
#include
#include
#include
#include


using namespace std;
bool IsVowel(char c);


int main(int argc, char *argv[])
{
int VowelCount = 0;
cout << "Enter a string of text: " << endl << flush;
char c;

while (cin.get(c)) {
if (IsVowel(c))
VowelCount++;
}


cout << endl << endl;
cout << "There were " << VowelCount << " vowels" << endl;
return 0;
}



bool IsVowel(char c)
{
c = toupper(c);


switch (c)
{

case 'A': case 'E': case 'I':
case 'O': case 'U': case 'Y':
return true;
}

}

Of course is in C++

Answer 1

use std::string str;
cin >> str;
Now search for vowels in the string

Answer 2

Your function IsVowel always returns true, so it should return by default false unless one of the vowels appear;
I also modified your code where you read the input;
Instead of attempting to read charcter by character, which is also implemented wrong in your code unless you use the non-standard conio "getch()".
So instead I replaced that part with a simple code which reads a string and then iterates through the string to count the vowels.

#include
#include
#include
#include

using namespace std;
bool IsVowel(char c);

int main(int argc, char *argv[])
{
int VowelCount = 0;
cout << "Enter a string of text: ";
string str;
getline(cin,str);
for (unsigned int i = 0; i < str.size(); i++){
if (IsVowel(str.at(i)))
VowelCount++;
}
cout << endl << endl;
cout << "There were " << VowelCount << " vowels" << endl;
system("pause");
return 0;
}

bool IsVowel(char c)
{
c = toupper(c);
switch (c)
{
case 'A': case 'E': case 'I':
case 'O': case 'U': case 'Y':
return true;
}
return false;
}