English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

a 5.0 MeV (kinetic engery) proton enters a .20-T field, in a plane perpendicular to the field. What is the radius of its path?

Please provide step-by-step instructions. I've been trying to figure this out. Thank you!

2007-03-18 13:38:37 · 2 answers · asked by Sparkles 3 in Science & Mathematics Physics

Please do not be rude to me.

I know that the force pulling the wire up is the Magnetic force, and the one that pulls it down is the gravitational force.

So, 0 = -FG (gravitational force) + FB (Magnetic force)
0=-FG+FB
This coincides with:
0=ILB-MG

Since I am looking for current, I rearrange my equation to:
I=MG/LB

After here, I am stuck.

I DO NOT appreciate your rudeness. I am not a slacker, and I only ask for help when I absolutely need help. Yahoo Answeres is a place for people to ask questions and for the community to answer. If you don't have an aswer, then please don't post a reply. Thank you.

2007-03-18 14:46:10 · update #1

2 answers

My physics teacher told me that if you pick Newton's 2nd law to use for your equation, you will be right 90% of the time. I don't think that this one of those times however. Maybe if you squint your eyes and jump up and down like a monkey yelling "yippe" the answer will come to you. Seems to work for a good Asian friend of mine! LOL!

2007-03-19 15:43:51 · answer #1 · answered by Jessie L 2 · 0 0

I bet you have

2007-03-18 13:43:50 · answer #2 · answered by Anonymous · 0 2

fedest.com, questions and answers