a 5.0 MeV (kinetic engery) proton enters a .20-T field, in a plane perpendicular to the field. What is the radius of its path?
Please provide step-by-step instructions. I've been trying to figure this out. Thank you!
2007-03-18
13:38:37
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2 answers
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asked by
Sparkles
3
in
Science & Mathematics
➔ Physics
Please do not be rude to me.
I know that the force pulling the wire up is the Magnetic force, and the one that pulls it down is the gravitational force.
So, 0 = -FG (gravitational force) + FB (Magnetic force)
0=-FG+FB
This coincides with:
0=ILB-MG
Since I am looking for current, I rearrange my equation to:
I=MG/LB
After here, I am stuck.
I DO NOT appreciate your rudeness. I am not a slacker, and I only ask for help when I absolutely need help. Yahoo Answeres is a place for people to ask questions and for the community to answer. If you don't have an aswer, then please don't post a reply. Thank you.
2007-03-18
14:46:10 ·
update #1