Chemistry help!?

Question

Two moles of H2O(g) at 1.00 atm and 100.°C occupy a volume of 61.2 L. When two moles of H2O(g) are condensed to two moles of H2O(l) at 1.00 atm and 100.°C, 81.32 kJ of heat is released. If the density of H2O(l) at this temperature and pressure is 0.996 g/cm3, calculate E for the condensation of two moles of water at 1.00 atm and 100.°C in kJ.

Answer 1

What is E?

Is it the enthalpy change of condensation?

If so then your answer is -81.32 kJ/mol.