Harold bought 2 pairs of sandals for the same price. He also bought a pair of socks for $3. How much did one pair of sandals cost if Harold spent a total of $31? Can you give me an algebraic equation also and the answer? Thank you SOOO much.
2007-03-18 11:37:34 · 9 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Let X = the cost of one pair of sandals
2X + 3 = 31 (X times 2 pair of sandals + $3 for the socks = $31 total) Now subtract 3 from each side of the equation. you get:
2X = 28 (divide each side by 2)
X = $14
2007-03-18 11:43:52 · answer #1 · answered by Faye H 6 · 1⤊ 0⤋
Let X = the cost of a pair of sandals.
He brought 2 pairs so we have 2x
He brought a pair of socks for $3
He brought 2 pairs of sandals that cost 2x + one pair of socks that cost $3 and he spent $31 for all.
2x + 3 = 31
2x = 28
x=14 so each pair of sandals cost $14
2007-03-18 11:45:09 · answer #2 · answered by kale_ewart 5 · 1⤊ 0⤋
A) Two times a pair of sandals plus one pair of socks = $31
B) 0ne pair of socks = $3
C) A) above minus B) above: two pair of sandals = $28
D) $28 divided by 2 = $14, the cost of 1 pair of sandals
OR
2X + 1 Y = $31
1Y = $3
SUBTRACTING, 2X = $28
DIVIDING BY 2, X = $14
2007-03-18 11:47:45 · answer #3 · answered by Husker41 7 · 0⤊ 0⤋
31-3=28
28/2=14
1 pair of sandals = $14
2007-03-18 11:46:34 · answer #4 · answered by Ritika 97 2 · 1⤊ 0⤋
2x+3=31 31-3=28 28 divided by 2=14 1pair is 14$
2007-03-18 11:46:27 · answer #5 · answered by nvrrong 5 · 1⤊ 0⤋
$31 - $3 = $28 ÷ 2 = $14.00
2007-03-18 13:30:23 · answer #6 · answered by Çåŗőľîņẫ§ħŷġĭ®ł 5 · 0⤊ 0⤋
2x+3=31
2x=31-3
2x=28
x=14
2007-03-18 11:46:09 · answer #7 · answered by ♫O Praise Him♫ 5 · 1⤊ 0⤋
2x + 2 = 31
2x = 29
x = 14.5
$14.50 = 1 pair of sandals
2007-03-18 11:40:15 · answer #8 · answered by crzywriter 5 · 0⤊ 3⤋
$15.5 each for 2 pair of shoes.. hekka easy problem
2007-03-18 11:41:46 · answer #9 · answered by Anonymous · 0⤊ 2⤋