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Plane Trigonometry, Part 3


1. Find the sine, cosine, tangent and cotangent of :
a. sin122° ≈ 0.848048
cos122° ≈ -0.529199
tan122° ≈ -1.6003345
cot122° = 1/tan122° ≈ -0.62486935

b.sin315° 12' ≈ -0.7046342
cos315° 12' ≈ 0.7095707
tan315° 12' ≈ -0.9930429
cot315° 12' = 1/tan315° 12' ≈ -1.0070058

c. sin275° 13’ 37” ≈ -0.995841667
cos275° 13’ 37” ≈ 0.09110090
tan275° 13’ 37” ≈ -10.9311941
cot275° 13’ 37” = 1/tan275° 13’ 37” ≈ -0.09148134

d. sin193° 41’ 51” ≈ -0.236795754
cos193° 41’ 51” ≈ -0.971559453
tan193° 41’ 51” ≈ 0.243727497
cot193° 41’ 51” = 1/tan193° 41’ 51” ≈ 4.10294288

2007-03-18 11:02:49 · 3 answers · asked by help 1 in Education & Reference Teaching

3 answers

When I checked your calculations with my TI-84 Plus Calculator--YOU WERE CORRECT.

Good Luck....

2007-03-18 11:59:21 · answer #1 · answered by Teacher Man 6 · 0 0

something is faulty right here, because of the fact cosine (or sine) can never be below -a million or greater suitable than a million. the two sine and cosine must be between -a million and a million, and -7/5 is out of the form. besides the fact that if for c) sin²? + cos²? , this consistently equals one, no matter what the attitude is. For the logarithms: ln x - 2 ln (x²+a million) + ½ ln (3 + x^4) = ln x - ln (x² + a million)² + ln ?(3 + x^4) = ln x?(3+x^4)/(x²+a million)² this is it! ;)

2016-10-19 00:35:31 · answer #2 · answered by ? 4 · 0 0

You could confirm your answers by looking them up in a set of trig tables, or if you have a top end calculator, you can run them through it.

2007-03-18 11:07:51 · answer #3 · answered by St N 7 · 0 0

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