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Batches of 200,000 reads of (A+T)-rich DNA were generated and new genome assemblies were reassessed.
After four such batches were added to the assembly, representing about 30% of the data, coverage of the (A+T)-rich regions had improved to 6-fold and the N50 (N50 is the contig size where 50% of the genome sequence is in contigs of size N50 or larger) of contigs had doubled to over 30 kilobases (kbstatistics adequate for gene predictions and analysis. In total, 1.8 gigabases (Gb) were assembled, 7.5 coverage of the (clonable) 236 megabase (Mb) honeybee genome

2007-03-18 10:48:44 · 2 answers · asked by Anonymous in Science & Mathematics Biology

2 answers

First sentence: DNA sequencing reactions were performed in groups of 200,000. This data was fed to a computer which tries to assemble the short sequences into large fragments of the chromosomes.

Second sentence: 800,000 sequencing reactions were used, resulting in new fragments with 50% of the genome sequence contained in computer-assembled fragments of greater than 30 kb. In these assemblies, each base had been sequenced no fewer than 6 times, meaning there was significant condifence in the accuracy of the sequencing reactions, and the computer assembled fragments.

Third sentence: Overall, the computers were given 1.8 billion bases of DNA, which they turned into a series of chromosomes totally 236 million bases, on average sequenced 7.5 times each.

2007-03-19 01:55:04 · answer #1 · answered by John V 4 · 0 0

are u serious... this is the transcription, and after the reproduction of DNA...

2007-03-18 18:22:18 · answer #2 · answered by aloha_bgd 2 · 0 1

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