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2007-03-18 10:35:13 · 2 answers · asked by kevin n 1 in Science & Mathematics Chemistry

2 answers

H2SO4

mass of H = 2(1.01) = 2.02
mass of S = 1(32.1) = 32.1
mass of O = 4(16.0) = 64.0
the numbers in () are the atomic masses of each element

total mass = molar mass = 98.1 g/mole

% of each element = (total mass of element / total mass) x 100%

% H = (2.02 / 98.1) x 100% = 2.06 % H
% S = (32.1 / 98.1) x 100% = 32.7 % S
% O = (64.0 / 98.1) x 100% = 65.2 % O

2007-03-18 10:50:41 · answer #1 · answered by chem geek 4 · 0 0

Well sulfuric acid is pure. You can dilute it with water, in which case your would then be able to prepare a percent concentration.

If I missed the point, it is H2SO4, which implies the percentage constituents.

2007-03-18 17:44:09 · answer #2 · answered by KirksWorld 5 · 0 0

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