physics watt energy Q?

Question

an all electric household used 3820 kilowatt hours of energy a month. it cost 230 dollars. what average rate (cost per kilowatt hour was charged)?

Answer 1

3820 ÷ 230 = $16.61 per kwh

Answer 2

u must be kidding me. its just 230/3820. that is the cost per kilowatt hour.

Answer 3

Are you sure this s a quistion?
its just 3820 / 230 = 16.609

Answer 4

For this question, you are able to think of roughly U = q + w because of the fact the guy till now suggested, artwork would be none on the grounds that there is not any replace in quantity, hence inner potential equals the thermal potential i.e. U = q all of us be attentive to that thermal potential is given as a cost, one hundred twenty five W or one hundred twenty five J/s and we are given a time, on your case 10 min the formulation for U is 3/2NkT the place N = form of molecules ok = Boltzmann's consistent; a million.38 * 10^-23 J/ok T = what we are attempting to discover, as a effect it rather is going to be a transformation in T because of the fact the Q added will influence U, which impacts variables N & T (and the quantity of molecules won't rather boost) Q might nicely be calculated as ability * time (they gave ability as a cost of 125W for thermal potential) hence, T = 2P*t / (3N*ok) and you gets 6.03 kelvin, or as a effect celsius. gadgets right here for temp are the comparable between kelvin and celsius on the grounds that this bargains with replace in temp, and the replace in temp in kelvin will consistently be the comparable in replace in terms of celsius. tl;dr plug into right here what you have (conversions already taken under consideration): T = 2*(thermal potential cost)*(time)*60 / (3 * form of gas molecules * a million.38*10^-23)

Answer 5

6.021 cents per KWH.

Doug