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a) 0.050 L of 0.250 M CH3COOH + 0.100 L of 0.250 M NaOH


b) 0.050 L of 0.250 M CH3COOH + 0.100 L of 0.250 M HCl


c) 0.050 L of 0.250 M CH3COONa + 0.100 L of 0.250 M HCl


d) 0.100 L of 0.250 M CH3COONa + 0.050 L of 0.250 M HCl


You must enter all true statements in one continous alphabetical group, no spaces between the letters you enter.

2007-03-18 08:12:27 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

d only - in all the others the HCl or NaOH is in excess.

2007-03-19 07:19:24 · answer #1 · answered by Gervald F 7 · 0 0

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