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This is my fantasy baseball automatically picked team.

C - Jason Varitek
1B - Justin Morneau
2B - Robinson Cano
3B - Chipper Jones
SS - Rafeal Furcal
OF - Ichiro Suzuki
OF - Magglio Ordonez
OF - Delmon Young
Util -Hank Blalock
Bn - Morgan Ensberg
Bn - Mark Teahen
Bn - Jim Edmonds
Bn - Mark Loretta

SP - Johan Santana
SP - Felix Hernandez
RP - Jonathoan Papelbon
RP - Joe Borowski
P - Erik Bedard
P - Ervin Santana
P - Brad Penny
Bn - Mark Buerhle

Any ideas on how I can improve my team.
12 team leauge - Head to Head

2007-03-18 07:48:22 · 4 answers · asked by the Jam 2 in Sports Fantasy Sports

4 answers

Pretty good team there, but I can make a few suggestion concerning your roster:

-With Blalock, Teahan and Ensberg on your roster, your better off trading Chipper Jones to someone who desperate for a 3B or a Util. Some trade baits for Jones includes Jeremy Bonderman, Nick Swisher, John Smoltz, Chris Young, Jason Schmidt, Chris Ray, Brian Fuentes, Curt Schilling, and Felix Hernandez.

-Mark Loretta is going to be the super utility player for Houston, so he's going to get one or two starts a week, which doesn't warrant a roster spot for him.

-Edmonds is clearly not the same player as he use to be and as long as he's playing CF, his injuries is going to take a toll on his numbers. For his price, you can get Ken Griffey Jr., Scott Podsednik, Chris Duffy, Matt Murton, Craig Monroe, or Kevin Youkilis.

2007-03-19 07:29:36 · answer #1 · answered by mojo8983 5 · 0 0

Sweet team... i like the mix of power and steals in your lineup and guys like Ensberg and Teahan on the bench...

just one thing - get rid of Loretta/Edmonds and add a closer or 2... Papelbon isn't closing this year and Borowski is serviceable but not the greatest closer by any means...

2007-03-18 20:32:52 · answer #2 · answered by ryan99n2000 3 · 0 0

Trade Morgan Ensberg for either a catcher, outfielder or a relieve pitcher.

2007-03-18 14:54:15 · answer #3 · answered by Jake 6 · 0 0

not bad... maybe get a few different pitchers

2007-03-18 14:53:17 · answer #4 · answered by man with the answers 1 · 0 0

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