how to calculate electric flux if the charge is inside 1. the centre of thecubeor hemisphere2at corner of cube

Answer 1

Using Gauss theorem,the electric flux through the surface of cube or hemisphere is one over epsilon not times charge enclosed within. ( epsilon not is absolute permittivity of vacuum)


In case2,when the charge is on the corner of a cube ,only 1/ 8 of flux is linked to this cube (because a corner is shared by eight cubes)

In case 2, flux = (1/8 ) (charge on corner) / epsilon not

Answer 2

eletric flux (phi) by surace section A may be got here across be making guassian floor of structure dice phi = finished flux = q(centre)/eo considering that its dice > equivalent flux will go by each of 6 faces phi (face) = phi(finished)/6 = q(centre)/6 eo in spite of be the quantity, flux relies upon on the sturdy attitude in spite of in case you amplify your dice to bigger fee of volume, the flux will be determined by ability of the fee, and not in any respect the dimensions of guassian floor. evaluate visalising a 30 degree attitude (V structure) blocked by ability of regularly occurring parts a1, a2, a3..... a1< a2