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a) 0.100 L of 0.250 M CH3COOH + 0.050 L of 0.250 M NaOH


b) 0.100 L of 0.250 M CH3COOH + 0.050 L of 0.250 M HCl


c) 0.050 L of 0.250 M CH3COONa + 0.100 L of 0.250 M HCl


d) 0.100 L of 0.250 M CH3COONa + 0.050 L of 0.250 M HCl



It's not b, bd, or d.

Any help with an explaination is appreciated. Thank you.

2007-03-18 07:03:39 · 1 answers · asked by Katdabrat 2 in Science & Mathematics Chemistry

1 answers

In a, half of the acid is neutralised, leaving half of the acid unchanged = a buffer.

In d, half of the salt is changed back into the acid, leaving half the salt = a buffer.

2007-03-20 07:31:49 · answer #1 · answered by Gervald F 7 · 0 0

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