What was the mass of alcohol? Details Below.?

Question

A certain mass of pure grain alcohol at a temperature of 25C is mixed with 200 grams of water at 75C. The final temperature of the mixture is 50C.
Given- Water 4.18 J.(grams perdegress)C, 1.00 cal/(G per degress C)
Grain Alcohol- 2.4 J, .58 cal

Please Help with Colrimetry problem.
Grain Alcohol- 2.3 J

excuse the bottom grain alcohol it is 2.4

Answer 1

m(50 - 25)(0.58) = 200(75 - 50)(1)
14.5m = 5,000
m = 5,000/14.5
m = 344.83 g