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4a(3x+5)
1.2c(3c+5)
3e(2e to the(2nd power)-5e)
7f(3f(to the 2nd power)+f)

2007-03-18 05:24:43 · 1 answers · asked by Diamond E 1 in Science & Mathematics Mathematics

1 answers

4a(3x+5)
=12ax + 20a

1.2c(3c+5)
= 3.6 c to the (power 2)+ 6c

3e(2e raised to the power 2 -5e)
=6e (raised to the power 3) - 15 e

7f (3f to the power 2 + f)
= 21f to the power 3 + 7f to the power 2

2007-03-18 06:00:43 · answer #1 · answered by Sarah Koshy 2 · 0 0

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