Sally bought three chocolate bars and a pack of gum and paid $1.75. Jake bought two chocolate bars and four p

Question

packs of gum and paid $2.00. Find the cost of a chocolate bar and the cost of a pack of gum.

Answer 1

x=chocolate bars
y=packs of gum

3x+y=1.75
2x+4y=2.00

Multiply the first equation by -4:
-12x-4y=-7.00
2x+4y=2.00
===========
-10x=-5.00
x=.50

2(.50)+4y=2.00
1+4y=2.00
4y=1.00
y=.25

The chocolate bars costs 50 cents and the packs of gum costs 25 cents.

Check:
3(.50)+.25=1.75
1.50+.25=1.75
1.75=1.75

2(.50)+4(.25)=2.00
1.00+1.00=2.00
2.00=2.00

I hope this helps!

Answer 2

Let x= cost of chocolate bar
Let y= cost of gum
3x+y=1.75 ;subtract 3x and isolate y: y=1.75-3x
2x+4y=2
Now, substitute y for y in the second equation
2x+4(1.75-3x)=2
2x+7-12x=2
-10x=-5
x=1/2 or 50 cents
Now plug in x for the other equation
3(1/2)+y=1.75
1.5+y=1.75
y=.25 or 25 cents

Answer 3

The chocolate bars cost 50cent and the gum cost 25cent

Answer 4

the chocolate bars are 50cents each and the gum is 25 cents

Answer 5

easy **** yo,
let x represent the chocolate bars and y represent the gum aight.
3x+y=1.75
2x+4y=2
now u have to eliminate one of the factors.
y would be the easiest; you multiply the first equation by -4
-12x-4y=-7
2x+4y=2 (remains the same)
now u got
-10x=-5
therefore x=-5/-10=0.5
now that u got x u sub it into either one of the equations
2(0.5)+4y=2
1+4y=2
4y=2-1
4y=1
y=1/4=0.25
so x=0.5 and y=0.25

Answer 6

take the cost of a chocolate bar to be p and the cost of a pack of gum to be q.

therefore,

3p+q=1.75..........eq(i)
2p+4q=2.............eq(ii)

Multiplying eq(i) with 4 and subtracting it from eq(ii)

2p+4q=2
-(12p+4q=7)

you get

-10p= -5
10p=5
p=0.5

Putting the value of p in eq(i), we get

3*0.5+q=1.75
1.5+q=1.75
q=1.75-1.5
q=.25

So, the cost of a chocolate bar is 50 cents or $0.5, and the cost of a pack of gum is 25 cents or $0.25