word problems?

Question

a train covers a certain distance at a uniform speed. if the train would have been 10km/hr faster, it would have taken 2 hours less than the scheduled time. And ,if the train were slower by 10km/hr , it would have taken 3 hours more than the scheduled time. find the distance covered by the train.

Answer 1

Um what he said lol...

Answer 2

I will tell you the answer first and remember i am the first to answer
The distance coverd by train is 600Km

if you want details please send me an email because there are 3 varibale equition solving and its long

you can check it the resolves are
D = distance in Km 600Km
T schadual time in hours 12h
V uniform speed 50Km/h

case one + 10Km/h
T=D/V = ( 600 ) / ( 50 + 10 ) = 10 two hours early

case two -10Km/hour
T=D/V = ( 600 ) / ( 50 - 10 ) = 15 three hours late

please remember I am the first one to solve it
and Its a good quistion

Answer 3

The train travels at speed v, covering distance x in time t.

v = x/t

Now if the speed is v+10, then it covers x in t-2.
v+10 = x/(t-2)
If the speed is v-10, then it covers x in t+3
v-10 = x/(t+3)

Substitute the first expression in the second and third to eliminate v and leave you with just x and t. Then solve the pair of simultaneous equations for x.

Answer 4

rt=d
(r+10)(t-2)=d
(r-10)(t+3) =d
(r+10)(t-2)=rt
(r-10)(t+3) =rt
r= 50 kmph (normal speed)
t= 12 hours (normal time)
d= 600 km (constant distance)
60*10 = 600
40*15= 600

Answer 5

distance= average speed*time

therefore,
xt=(x+10)(t-2)
or, xt=xt+10t-2x-10
or, 10t-2x=10...............eq(i)

and,
xt=(x-10)(t+3)
or, xt=xt-10t+3x-30
or, -10t+3x=30...............eq(ii)

Adding eq(i) to eq(ii)

10t-2x=10
-10t+3x=30

we get,

x=40

Putting the value of x in eq(i), we get,

10t-2*40=10
10t=10+80
10t=90
t=9

therefore the distance covered= x*t

=40*9
=360 km

Answer 6

lost ya at first breath..