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Simplify:

√[81x^8y^12z^20]

I'm not sure if you will be able to see the square root sign in front of this expression. I have tried to simplify this, and came up with two completely different answers. I need help! Please and thank you.

2007-03-18 03:27:50 · 5 answers · asked by Brackish 1 in Science & Mathematics Mathematics

5 answers

sqrt of 81=9
when finding sqrt you divide exponents by 2

answer 9 x^4 y^6 z^10

2007-03-18 03:45:39 · answer #1 · answered by Dave aka Spider Monkey 7 · 0 0

[(?5)^3(?9)] ^ 2 rewrite as a fragment exponent, the place the numerator is the form of circumstances the quantity multiplies itself with the help of and the denominator is the nth root the quantity is taken with the help of [5^(a million/2) circumstances 9^(a million/3)] ^ 2 notice that we are in a position to rewrite 9 as a ability of three! [5^(a million/2) circumstances (3^2)^(a million/3)] ^ 2 regulation of exponents; to the flexibility of a ability, multiply the exponents [5^(a million/2) circumstances 3^(2 x a million/3)] ^ 2 [5^(a million/2) circumstances 3^(2/3)] ^ 2 regulation of exponents; to the flexibility of a ability, multiply the exponents 5^(a million/2 circumstances 2) circumstances 3^(2/three times 2) 5^(2/2) circumstances 3^(4/3) 5^a million circumstances 3^(4/3) and in case you desire, placed lower back into radical variety 5 circumstances ^3?(3)^4 5 circumstances ^3?3^three times ^3?3^a million 5 circumstances 3^(3/3) circumstances ^3?3 5 circumstances 3^a million circumstances ^3?3 5 circumstances three times ^3?3 15(^3?3) can no longer simplify added

2016-10-18 23:56:12 · answer #2 · answered by schwalm 4 · 0 0

9x^4y^6z^10
its not +/- becuz the radical sign is
not accompanied by a negative sign
if y^2=x
only then y=+/-√x
if y=√x
then y=+ roots

2007-03-18 03:39:03 · answer #3 · answered by Maths Rocks 4 · 0 0

√[81x^8y^12z^20]= 9x^4y^6z^10

2007-03-18 04:34:58 · answer #4 · answered by kapilbansalagra 4 · 0 0

+- (9x^4y^6z^10)

2007-03-18 03:37:46 · answer #5 · answered by leo 6 · 0 0

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