PQRS is a parallelogram.
If :
PQ =4x+1
QR=3x-2
RS=x+5
What is the measure of the sides of PQRS and its perimeter?
2007-03-18 01:41:11 · 3 answers · asked by Itachi 1 in Education & Reference ➔ Homework Help
PQ = RS, therefore
4x + 1 = x + 5
3x = 4
x = 4/3
PQ = RS = 4x + 1
= 4(4/3) + 1
= 19/3
QR = SP = 3x - 2
= 3(4/3) - 2
= 4 - 2
= 2
the perimeter of PQRS = PQ + QR + RS + SP
= 19/3 + 2 + 19/2 + 2
= 50/3
= 16 2/3
2007-03-18 01:59:34 · answer #1 · answered by Anonymous · 0⤊ 0⤋
PQ parallel to RS, hence 4x+1 = x+5.
Obtain x = 4/3, PQ=4x4/3 = 5 and 1/3.
Then QR = 3 times 4/3 minus 2 = 2
SP parallel to QR = 2
The total perimeter becomes 2 x 5 1/3 + 2 x 2 = 14 2/3.
2007-03-18 02:15:03 · answer #2 · answered by autor06hj 2 · 0⤊ 0⤋
opposite sides of a parallelogram are congruent
4x+1 = x+5
x= 4/3
Plug x in for each of the equations to get a side measure
The missing side is the same measure as RS
Then add all of the sides together to get the perimeter
2007-03-18 01:47:17 · answer #3 · answered by HockeyChick 3 · 0⤊ 0⤋