2007-03-18 01:23:42 · 13 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
PERIMETER = 2L+2W
32 = 2*12+2W
2W = 32 - 24
2W = 8 dividing by 2
w = 4 cm
2007-03-18 01:48:51 · answer #1 · answered by emy 3 · 0⤊ 0⤋
4
2007-03-18 02:44:44 · answer #2 · answered by MaryJAyJay 2 · 0⤊ 0⤋
Perimeter = 2 x wdth + 2 x length
==> Width = (perimeter - 2 length)/2 = 8/2 = 4
2007-03-18 01:33:16 · answer #3 · answered by physicist 4 · 0⤊ 1⤋
let say the width is "w" and the length is "L"
Perimeter of the rectangle = W + W + L + L
given the perimeter = 32 and the length is 12
so, W + W + 12 = 32
2W = 32 - 12
2W = 20
W = 10
the width of the rectangle is 10 cm
2007-03-18 01:37:54 · answer #4 · answered by Anonymous · 0⤊ 2⤋
Perimeter = 32 cm = 2 x (W+L)
L = 12
Substituting gives,
W+12 = 16
Therefore, Width = 4 cm
2007-03-18 01:27:40 · answer #5 · answered by sir_knowalot 2 · 0⤊ 1⤋
Perimeter=2x length + 2x width
so
32 = 2x12 + 2x width
so
2x width = 8
so width = 4
2007-03-18 01:58:45 · answer #6 · answered by calvin o 5 · 0⤊ 0⤋
Perimeter Formula
P = 2L + 2W
32 = 2(12) + 2W
32 = 24 + 2W
32 - 24 = 24 + 2W - 24
8 = 2W
8 / 2 = 2W / 2
8 / 2 = W
4 = W
The width is 4 cm
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2007-03-18 03:28:22 · answer #7 · answered by SAMUEL D 7 · 0⤊ 0⤋
w=width
L=length
p=perimeter
The formula for perimeter: 2L+2w=P
in this situation, the perimeter is 32 and the length is 12. Use algebra:
2(12)+2w=32
24+2w=32
2w=8
w=4
The width is 4.
Check.
2(12) + 2(4) = 32
24+8=32
32=32
Hope that helps!
2007-03-18 01:30:04 · answer #8 · answered by BlueSmiley 3 · 0⤊ 1⤋
P = 2L + 2w
32 = 2(12) + 2w
32 - 24 = 2w
2w = 8
w = 8/2
w = 4
Answer: width = 4cm.
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2007-03-18 03:12:59 · answer #9 · answered by aeiou 7 · 0⤊ 0⤋
4 cm....If the length is 12cm (multiplied by 2 = 24cm), take this away from the total perimeter = 8cm. Divide by 2....Bingo!! 4cm.
2007-03-18 01:30:18 · answer #10 · answered by pure_dragonfire 4 · 0⤊ 1⤋