2007-03-16 19:31:27 · 4 answers · asked by Emily S 1 in Science & Mathematics ➔ Mathematics
the equation is that of a parabole.
Axis of symmetry at the minimum when first derivative =0
dy/dx = 6x-7 root is x=7/6
so line parralel to ordinate axis passing through X=7/6
2007-03-16 19:38:33 · answer #1 · answered by maussy 7 · 0⤊ 0⤋
Putting
y = 3x^2 - 7x - 8
into vertex form,
y = 3(x^2 - (7/3)x) - 8
y = 3(x^2 - (7/3)x + 49/36 - 49/36) - 8
y = 3(x - 7/6)^2 - 49/12 - 72/12
At this point we have determined that the axis of symmetry is x = 7/6
2007-03-17 02:52:11 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
The axis of symmetry is x=-b/2a.
x=-(-7)/(2)(3)
x=7/6
2007-03-17 02:45:53 · answer #3 · answered by dcl 3 · 0⤊ 0⤋
y = 3.[ x² - (7/3).x - 8/3 ]
y = 3.[ (x² - (7/3).x + 49/36) - 49/36 - 8/3]
y = 3.[(x - 7/6)² - 49/36 - 8/3]
Axis of symmetry is x = 7/6
2007-03-17 11:10:20 · answer #4 · answered by Como 7 · 0⤊ 0⤋