I don't care the price nor the brand. Just the quality!
2007-03-16 19:25:09 · 11 answers · asked by Anonymous in Computers & Internet ➔ Hardware ➔ Desktops
I have 2.00 GHz
2007-03-16 19:54:16 · update #1
run a crucial scan at http://www.crucial.com
2007-03-16 19:27:53 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Vista X32 would understand as much as 3gb no remember what version, yet there's a patch so as that it's going to understand 4gb. top rate ought to run on 1gb, with little issues. 1gb with problem-loose is plenty.
2016-12-18 15:51:20 · answer #2 · answered by ? 4 · 0⤊ 0⤋
You need to know exactly what type of memory you can use, my 2Gb of Patriot DDR2 800 is very good, cheaper than most that people have been recommending and yet out performing them too (it's actually rated to 1000MHz but I haven't bothered messing with my motherboard timings yet).
Once you know what type of RAM you can use check the reviews at tomshardware.com, hardocp.com and anandtech.com. Memory costs quite a lot and you owe it to yourself to get the real lowdown rather than asking a bunch of random people most of whom don't know a thing and still speak with certainty.
2007-03-16 20:13:11 · answer #3 · answered by Chris H 6 · 0⤊ 0⤋
Kingston DDR Ram.
2007-03-16 19:32:26 · answer #4 · answered by Anonymous · 0⤊ 0⤋
CORSAIR XMS2 1GB
model: CM2X1024-6400PRO
for detail: http://www.newegg.com/Product/Product.aspx?Item=N82E16820145588
2007-03-16 19:41:44 · answer #5 · answered by sayan dey 1 · 0⤊ 0⤋
if you don't care about the price then Kingston is the way to go (lifetime guarantee)
2007-03-16 19:40:14 · answer #6 · answered by Anonymous · 0⤊ 0⤋
hi you using in 352 mb no 532 mb purchase in online
now. go to ebay
2007-03-16 19:29:30 · answer #7 · answered by Rajkumar 2 · 0⤊ 1⤋
id use at least 2gb...preferably DDR2 or atleast DDR 400.
2007-03-16 19:32:48 · answer #8 · answered by Joshua 3 · 0⤊ 1⤋
kingston
2007-03-16 20:22:54 · answer #9 · answered by tdapower 3 · 0⤊ 0⤋
buy crucial
2007-03-16 19:28:11 · answer #10 · answered by ryan_macalinao5472 3 · 0⤊ 0⤋