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Let f(x)=x^5+2x^3-2

a) show that f has exactly one zero
b) use the Intermediate Value Theorem to locate the interval where the zero lies in
c) use Newton's method to approximate the zero to 5 decimal place accuracy

2007-03-16 19:07:00 · 2 answers · asked by Fahion_Gal 1 in Science & Mathematics Mathematics

2 answers

a)
There is only one sign change among the coefficients, hence there is only one zero. (I think it's called the Theorem of Rational Roots)
b)
if x = 0, f(x) = -2
if x = 1, f(x) = 0
hmmmmmmmmmmmmm
c)
Having chanced on the root, I don't think I'm up to Newton's method. It gets real tedious real fast for a function like this.
x1 = (0 - x0^5 - x0^3 + 2)/(5x0^4 + 6x0^2) + x0

2007-03-16 19:25:55 · answer #1 · answered by Helmut 7 · 0 0

Do your own homework. It is the only way you will learn.

2007-03-17 02:15:06 · answer #2 · answered by Christie D 5 · 0 0

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