If tn=4n+5,what is the value of n?

Answer 1

Assuming by "tn" you mean n times another variable called t:

tn = 4n + 5

Subtract 4n from both sides:

tn - 4n = 5

Factor out n:

n(t - 4) = 5

Divide both sides by t - 4:

n = 5/(t - 4)

Answer 2

If tn = 4n +5 or tn - 4n =5 or n(t - 4) = 5 or n = 5/(t - 4)

Answer 3

tn=4n+5 add -4n to both sides and factor n then
(t-4)n=5 now devide both side to t-4 then n=5/t-4 and note that t is not 4, otherwise by subistituting in the original equation we have 4n=4n+5 which leads to the obsurdity 0=5!

Answer 4

Is the question asked is correct ? If it is correct then you can refer the above answers.
OR you want to ask the sum of n numbers
Then Sum of n numbers = (n/2) × [a – (n–1)d]
where a = first number in this case t1 = 4 × 1 + 5 = 9
d = common difference in the numbers in the series.
For that you got 1st term = 9 as explain above.
2nd no. = 4 × 2 + 5 = 13
3rd no. = 4 × 3 + 5 = 17
4th no. = 4 × 4 + 5 = 21
So the series is 9, 13, 17, 21 -----
so the common difference in the series is 4
Therefore Sum of n numbers = (n/2) × {9 + (n-1) × 4}
Using this formula you can find the sum of n Numbers.

Answer 5

The value of 'n' is 5/t-4.If we get exact value of tn we can give you the exact value of n.
Ex: If tn=9,then 'n'=1.

Answer 6

Hey, this is an arithmatic progression (AP) problem......
the std formula is

Tn=a+(n-1)d
comparing the two equations
first term,a=5
common differece,d=4n / (n-1) (here)
but generally,
common difference, d=(second term)-(first term)
but u give me the AP series which consists of the last term, Tn
the general AP series is given by
a, a+d, a+2d,..................Tn
hence ur d=a+d-a=d
so if Tn is known then we can find the total number of terms, n present......
ur question is incomplete
check the question again...ok

Answer 7

tn - 4n = 5
n (t - 4) = 5

n = 5/ (t - 4)

Answer 8

Get the n's on the same side of the equals sign:
tn-4n=5
Factor out a GCF of n:
n(t-4)=5
Divide both sides by t-4:
n=5/(t-4)

Answer 9

The value of n is 5 /(t-4)

Answer 10

tn=4n+5
tn - 4n = 5
n (t - 4) = 5
n = 5 over(t - 4)
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