I know that Force of the person pushing the car is equal to mgsintheta, but I don't understand why we use sine instead of cosine (Force of the person is an x component right??)
2007-03-16 17:54:56 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Use sin because this represents the vertical component of force needed to push the car UP the incline.
Hence, F = 950*9.8*sin9 = 1456.4 N
Since, we are ignoring friction, there is no horizontal component of force necessary. Therefore the distance is purely vertical: 810 m x sin9 = 126.7 m
W = 1456.4 x 126.7 = 184,543 J
2007-03-16 18:15:44 · answer #1 · answered by DuckyWucky 3 · 0⤊ 2⤋
950sin9° is the component of the weight of the car parallel to the incline. This is the minimum force that must be used to push the car up the incline, giving a value for work of
W = 810*950sin9° = 120,376 joules
2007-03-16 18:31:29 · answer #2 · answered by Helmut 7 · 0⤊ 1⤋
you should provide your solutions to the right value. because you in undemanding words have 2 major figures for g (9.8ms/2) and the attitude (9.0 levels), you should in undemanding words provide your answer to 2 major digits. So 450000J or 4.5x10^5 J Your equation setup is real.
2016-12-02 03:09:05 · answer #3 · answered by ? 4 · 0⤊ 0⤋