Subtract. (y-2/y+3)-(y/2y+6)?

Answer 1

I'm going to assume you meant to write the equation as follows:

(y - 2) / (y + 3) - (y) / (2y + 6)

You first need to find a common denominator. In this case, that would be 2y + 6. The left term should be multiplied by 2:

2(y - 2) / (2y + 6) - (y) / (2y + 6)

Put the two terms together over the common denominator:

(2y - 4 - y) / (2y + 6)

And work out the numerator to get the right answer:
(y - 4) / (2y + 6)

Answer 2

Your equation is [y-2/y+3] - [y/2y+6]
Make a common denominator as (y+3)(2y+6) and simplify as...
= {[(y-2)(2y+6)] - [(y)(y-3)]} / {(y+3)(2y+6)}

= {2y^2 + 6y - 4y -12 - y^2 + 3y} / 2y^2 + 6y - 6y -18

= {y^2 + 5y -12} / {2y^2 - 18}

and that's the answer.

Answer 3

is it [(y-2)/(y+3)]-[y/(2y+6)]?
if it is, then

=[2(y-2)/2(y+3)]-[y/(2y+6)]
=(2y-4-y)/(2y+6)
=(y-4)/(2y+6)

Answer 4

you didn't write it very well
is it (y-2)/(y+3) or y - (2/y) or........
there are a lot of combinations without proper parenthesis

Answer 5

y could be anything because there is nothing after the =, there isn't even an =