I need to express the terms into sin and cos and simplify.
Equation 1: (secθ - 1)(secθ + 1)
So far, I have...
(1/cosθ - cosθ/cosθ)(1/cosθ + cosθ/cosθ). Do I need to distribute?
write the first trig function in term of the second trig function.
Equation 2: cotx; sinx
So far, I have...
(cosx/sinx) What do I do next?
Thanks for the help.
2007-03-16 17:46:15 · 4 answers · asked by shih rips 6 in Science & Mathematics ➔ Mathematics
Equation 1: (secθ - 1)(secθ + 1)
For this one, first expand the equation, which will give you (secθ)^2 + secθ - secθ -1 = (secθ)^2 -1 = (tanθ)^2 = (sinθ)^2/(cosθ)^2
Equation 2: cotx; sinx
For this one, simplify cotx into cosx/sinx. then, we know that (cosx)^2 + (sinx)^2 = 1, so (cosx)^2 = 1 - (sinx)^2, therefore cosx = sqrt(1 - (sinx)^2)
the answer is then sqrt(1 - (sinx)^2)/sinx
2007-03-16 20:07:00 · answer #1 · answered by Motoko 3 · 0⤊ 0⤋
Question1
An equation requires = sign so you have an expression rather than an equation.
Expression 1
I will use Ø as I can`t find theta!
(1/cos Ø - 1).(1/cos Ø + 1)
= (1/ cos² Ø) - 1
= [(1 - cos² Ø) / cos² Ø ]
= sin² Ø / cos² Ø
= tan² Ø
Expression 2
(cos Ø / sin Ø).(sin Ø) = cos Ø
2007-03-17 05:04:13 · answer #2 · answered by Como 7 · 0⤊ 0⤋
( 1/cos - cos/cos) (1/cos + cos/cos)
= [(1 - cos) (1+cos)] /cos
= (1 - cos^2) / cos
by the identity sin^2 + cos^2 = 1
= sin^2 / cos
2007-03-16 18:22:55 · answer #3 · answered by Hk 4 · 0⤊ 0⤋
(secx-1)(secx+1)
(secx)^2-1
=(tanx)^2 [trig identity]
2007-03-16 17:51:35 · answer #4 · answered by Pushpa V 1 · 0⤊ 0⤋