2007-03-16 17:45:26 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2m(5m-3)(4m+7) 1st mutiply the binomials using FOIL
2m(20m^2+35m-12m-21) combine like terms
2m(20m^2+23m-21) now multiply each term of the trinomial by 2m
40m^3+46m^2-42m
2007-03-16 18:44:09 · answer #1 · answered by yupchagee 7 · 13⤊ 0⤋
Since the order doesn't matter, I will multiply the last two factors first:
2m(5m-3)(4m+7)
2m(20m^2 + 35m - 12m - 21)
2m(20m^2 + 23m - 21)
Now distribute the 2m to get the final answer:
40m^3 + 46m^2 - 42m
2007-03-17 00:52:16 · answer #2 · answered by Sam 5 · 0⤊ 0⤋
2mx5m=
10m^2 = 10(squared)
2m-3= 2m-3 since they aren't like values.
so far: 10m^2+2m-3
2mx4m=
8m^2+2m+7
10m^2+8m^2=
18m^2
2m+2m=4m
-3+7=4
FINAL ANSWER should be:
18m^2+4m+4
2007-03-17 00:57:29 · answer #3 · answered by Anonymous · 0⤊ 1⤋
2m(5m-3)(4m+7)
=2m(20m^2+35m-12m-21)
=2m(20m^2+23m-21)
=40m^3+46m^2-42m
2007-03-17 01:12:57 · answer #4 · answered by Hanna 2 · 0⤊ 0⤋