Factor Completely. 8x^2+24x-32?

Answer 1

8x^2+24x-32
8(x-1)(x+4)

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8x^2+24x -32
Notice there's a factor of 8 in each term. Factor out 8
8(x^2+3x-4)

Now you need 2 numbers that add to 3, but multiply to -4.
You also know that one of these numbers will be positive and the other will be negative (positive * negative = negative)

Additionally, the positive number needs to be larger in magnitude than the negative to add to a positive 3.

(-1)(4) = -4 -1+4 = 3

8(x+4)(x-1)

Answer 2

Begin by factorizing out the 8 in the whole equation. this makes it easier.

8X^2+24X-32=8(X^2+3X-4)=8(X-1)(X+4)

Answer 3

If the equation is equal to zero, try the following instead:

8x^2+24x-32 = 0

Divide by 8:

x^2+3x-4 = 0

Now, look for two numbers that muliply to equal -4 and add to equal 3:

(x+4)(x-1) = 0

x = -4 and x = 1

Answer 4

8x^2+24x-32 factor out 8
8(x^2+3x-4)
8(x+4)(x-1)

Answer 5

take out 8

8 (x^2 + 3x - 4)

look for two numbers that multiply to -4 and add to 3

4 and -1

8 (x+4)(x-1)

hope this helps

Answer 6

8(x^2+3x-4)
=8(x-1)(x+4)