2007-03-16 17:42:21 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x^2-7x+6=0
(x-6)(x-1)=0
x-6=0
x=6
x-1=0
x=0
roots are 1, 6
2007-03-16 17:45:41 · answer #1 · answered by yupchagee 7 · 16⤊ 0⤋
x² + 7x + 6 = 0 x² + 7x = -6 x² + 7x + (7/2)² = -6 + (7/2)² (x + 7/2)² = -24/4 + forty 9/4 (x + 7/2)² = 25/4 x + 7/2 = ± 5/2 x = -7/2 + 5/2 or x = -7/2 - 5/2 x = -2/2 or x = -12/2 x = -one million or x = -6 it quite is winding up the sq., which consistently works, yet factoring, whilst it extremely works, is extra undemanding. x² + 7x + 6 = 0 (x + 6)(x + one million) = 0 x + 6 = 0 or x + one million = 0 x = -6 or x = -one million
2016-10-02 06:32:02 · answer #2 · answered by mayben 4 · 0⤊ 0⤋
(x-6)(x-1)
x=1 or 6
2007-03-16 17:45:52 · answer #3 · answered by Anonymous · 2⤊ 0⤋
x^2-7x=-6
x(x-7)=-6
x=6
x-7=-6
x=-6+7
x=1
X=1 & 6
This is the total breakdown of the problem so you can show your steps correctly without skipping steps.
2007-03-16 17:50:29 · answer #4 · answered by cobra427jah 2 · 1⤊ 0⤋
(x-1)(x-6)
2007-03-16 17:50:05 · answer #5 · answered by 7 · 0⤊ 0⤋
the roots are 1 and 6 (both positive)
2007-03-16 17:50:48 · answer #6 · answered by Anonymous · 0⤊ 1⤋
(x-1)(x-6)
set both equal to zero and you get x=1 and x=6
2007-03-16 17:45:56 · answer #7 · answered by Howdy! 5 · 1⤊ 0⤋
Use the Quadratic Formula. It should be in your book or notes.
2007-03-16 17:47:10 · answer #8 · answered by Anonymous · 0⤊ 1⤋
(x-6)(x-1)=0
x=6 and 1
do your own homework.
2007-03-16 17:44:54 · answer #9 · answered by Anonymous · 2⤊ 0⤋
Pay attention in class. This is basic algebra.
2007-03-16 17:50:23 · answer #10 · answered by me 2 · 0⤊ 1⤋