a) What is its efficiency?
b) It absorbs 100 J from the hot reservoir during each cycle, how much work does it do?
c) How much heat does it give off in each cycle?
d) What is the coefficient of performance of this engine it works as a refrigerator between these two reservoirs?
2007-03-16 17:25:54 · 2 answers · asked by bonjette 2 in Science & Mathematics ➔ Physics
A carnot engine on a P/V diagram is represented as a box and of course a thoretical thing whereas no engine is as efficient as a carnot.
Draw out the "Box" that represents the cycle That will be helpful to you
The thermal efficiency is a delta T/ 300 or
(300-70)/300=Eff.
So now you know the efficiency, then only
100J x Eff= actual work.
Heat Rejected or given off to sink = 100J - work= Heat Rejected to sink or given off
The COP is 1/EFF
READ YOUR THERMALDYNAMICS BOOK !!!!!!!!!
2007-03-16 17:35:25 · answer #1 · answered by James M 6 · 0⤊ 1⤋
the performance of a warmth engine is calculated by ability of an straightforward equation that's right here eff = Qh/(Qh-Ql) Qh = temperature of the nice and cozy reservoir Ql = temperature of the chilly reservoir once you simplify the equation it boils all the way down to eff = a million - Qh/Ql replace numbers and the priority may basically be undemanding algebra.. bear in options...THE TEMPERATURES should be IN ABSOLUTE TEMP....which ability they should be IN KELVIN...to covert from Celsius to kelvin basically basically upload 273.
2016-12-02 03:08:11 · answer #2 · answered by ? 4 · 0⤊ 0⤋