2007-03-16 17:01:06 · 5 answers · asked by mhelle 1 in Science & Mathematics ➔ Mathematics
That's the difference quotient that you work with in "precal", with the additional step of letting h = 0 after you've simplified it out of the denominator.
2007-03-16 17:15:01 · answer #1 · answered by Joni DaNerd 6 · 0⤊ 0⤋
I'm not sure what "defined as limit" means, but the derivative of 3x - 2 with respect to x is simply 3.
2007-03-17 00:03:50 · answer #2 · answered by dac2chari 3 · 0⤊ 0⤋
You do f`(x)=[f(x+h)-f(x)]/h
as h approaches 0....thats your limit
f`(x)=[[3(x+h)-2]-[3(x)-2]]/h
2007-03-17 00:05:32 · answer #3 · answered by ? 2 · 1⤊ 0⤋
my answer is at this link..
http://img178.imageshack.us/img178/1927/derivgb2.jpg
2007-03-17 00:19:31 · answer #4 · answered by M. Abuhelwa 5 · 0⤊ 0⤋
lim (x1->x2) f(x)=[f(x1)-f(x2)]/(x1-x2)= [(3x1-2)-(3x2-2)]/(x1-x2)=
[3x1-2-3x2+2]/(x1-x2)=3(x1-x2)/(x1-x2)=3
2007-03-17 00:35:48 · answer #5 · answered by djin 2 · 0⤊ 0⤋