i think i am doing it right, just not sure....
(g) acetyene (C2H2) reacts w/ oxygen (g) to form (g) carbon ioxide and (g) water. can someone please tell me if im on the righ track?????? PPPLLLEEEAASSE!
C2 H2 (g) + 5O (g) -> 2CO2 (g) + H2O (g)
i know im supposed to end w/balancing sides. this shows me i have 2-C, 2-H and 5- O on both sides, right???
2007-03-16 16:18:56 · 5 answers · asked by claudia 1 in Science & Mathematics ➔ Chemistry
2C2H2 +502 = 4CO2 + 2H2O i think is the balanced equation
you forgot that oxygen by itself is O2 not O
2007-03-16 16:28:10 · answer #1 · answered by softballviolinist14 3 · 1⤊ 1⤋
Well, I am a chemist.
You have the right idea for sure. Just remember that Oxygen is diatomic, this meens that in nature you will never find it in its pure form with only one atom. You want:
2C2H2 (g) + 5O2 (g) --> 4CO2 (g) + 2H2O (g)
Hope this helps. Keep up the right idea.
Wee Man.
2007-03-17 00:17:33 · answer #2 · answered by boychuka 3 · 0⤊ 0⤋
No. You have shown your oxygen (reactant) as monoatomic. Oxygen gas is ALWAYS diatomic (O2). All of the following are always diatomic: nitrogen gas (N2), oxygen gas (O2), hydrogen gas (H2) and all of the group 17 (VII) elements: flourine (F2), chlorine (Cl2), bromine (Br2), Iodine (I2), and Astatine (At2).
Try your equation again.
CHEMISTRY TEACHER
2007-03-16 23:40:51 · answer #3 · answered by CAROL P 4 · 0⤊ 0⤋
the equation which you have given is absolutely correct and its an balanced equation.
so buddy u r on the right track...............
2007-03-17 01:12:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
2C2H2 (g) + 5O2 (g) ==> 4CO2 (g) + 2H2O (g)
Softball14 is correct!...
2007-03-16 23:29:47 · answer #5 · answered by Brewmaster 4 · 0⤊ 1⤋