Please solve for "X" and explain the answer; Thanks :)
2007-03-16 16:07:11 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2x+3y=6
=>2x+3y-3y=6-3y [subtracting 3y from both sides]
=>2x=6-3y
=>2x/2=(6-3y)/2 [dividing both sides by 2]
=> x=(6-3y)/2 ans.
2007-03-16 16:59:51 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
I dont understand the x and y intercept yet this feels like a simultaneous equation to me. the 2nd equation is two cases the 1st one. So, 2(2x+3y) = 2(6) = 4x+6y = 12 So 12 = 12
2016-10-18 21:32:02 · answer #2 · answered by ? 4 · 0⤊ 0⤋
2x + 3y = 6
subtract 3y from both sides to isolate 2x:
2x + 3y - 3y = 6 - 3y
2x = 6 - 3y
divide both sides by 2 to get the equation in terms of x:
2x/2 = 6/2 - 3y/2
x = 3 - 1.5y
2007-03-16 16:14:07 · answer #3 · answered by rooster1981 4 · 0⤊ 1⤋
Subtract 3y from both sides:
2x=6-3y
Divide both sides by 2.
x=(6-3y)/2
OR
x=3-(3/2)y
2007-03-16 16:14:20 · answer #4 · answered by dcl 3 · 0⤊ 1⤋
2x+3y=6
2x =6-3y
x =3-3y/2
2007-03-16 16:23:14 · answer #5 · answered by vaidhee 2 · 0⤊ 1⤋
2x + 3y = 6
2x = 6 - 3y
x = (6 - 3y) / 2
x = 3 - 3/2 y
2007-03-16 16:18:13 · answer #6 · answered by M. Abuhelwa 5 · 0⤊ 1⤋
2x+3y=6
2x=6-3y
2x=3(2-y)
x=3(2-y)/2
2007-03-16 16:12:24 · answer #7 · answered by Vanessa L 1 · 1⤊ 0⤋
2x+3y=6
2x+3y-3y=6-3y
2x= -3y+6
2x/2=(-3y+6)/2
x= -3over2y+3
I am pretty sure that is right
2007-03-16 16:53:26 · answer #8 · answered by martinezk22 1 · 1⤊ 1⤋
x=(-3y+6)/2
x=-3/2*y+3
just rearrange
2007-03-16 16:10:21 · answer #9 · answered by ? 2 · 0⤊ 1⤋