Simplify (x + 2) / x over (x – 2) / 3 x
2007-03-16 16:01:56 · 7 answers · asked by archie g 1 in Science & Mathematics ➔ Mathematics
[(x + 2) / x] / [(x - 2) / 3x]
= [(x + 2) /x] * [3x / (x - 2)]
= [3x (x + 2)] / [x (x - 2)]
= 3(x + 2) / (x - 2)
= (3x + 6) / (x - 2)
2007-03-16 16:10:47 · answer #1 · answered by rooster1981 4 · 0⤊ 0⤋
When you say over i hope you mean divide (/) because thats how I'm going to work this out lol :)
(x+2)/x / (x-2)/3x remember your basics when doing fraction division you just multiply by the inverse:
(x+2)/x *3x/(x-2)
Then Multiply: 3x(x+2)/x(x-2)
Next simplify by getting rid of same things on top and bottom (x's first): 3(x+2)/(x-2) = (3x+6)/(x-2)
I think thats as far as you can go!
2007-03-16 23:14:16 · answer #2 · answered by David S 2 · 0⤊ 0⤋
Fractions are division so you can rewrite the expression:
[(x+2)/x]/[(x-2)/3x]
When you divide fractions you need to rewrite the first fraction, change division to multiplication, flip the second fraction:
[(x+2)/x][3x/(x-2)]
Cancel the x in the first fraction (in the denominator) with the x in the second fraction (in the numerator.
You're left with
[3(x+2)]/(x-2)
2007-03-16 23:10:40 · answer #3 · answered by dcl 3 · 0⤊ 0⤋
= (x + 2)/x / (x -2)/ 3x
= (x + 2)/x * 3x/(x - 2)
= (x + 2) * 3/(x - 2)
= 3(x + 2)/(x - 2)
= (3x + 6)/(x - 2)
2007-03-16 23:22:33 · answer #4 · answered by PANCAKE LOVER 04 1 · 0⤊ 0⤋
[(x+2)/x] / [(x-2)/3x]
= [(x+2)/x] * [3x/(x-2)]
= [(x+2)*3x] / [x*(x-2)]
= [(x+2)*3*x] / [x*(x-2)] {3x = 3 * x}
= [(x+2)*3] / (x-2) {x cancels out of num & denom}
= (3x + 6) / (x - 2)
2007-03-16 23:27:02 · answer #5 · answered by Anonymous · 0⤊ 0⤋
don't have a clue
2007-03-16 23:05:37 · answer #6 · answered by kingshanethe3rd 2 · 0⤊ 0⤋
sorry.. I cant do that! :(
2007-03-16 23:05:21 · answer #7 · answered by Shelly 3 · 0⤊ 0⤋