x^2+6x+11=0 I cant get this u cant simplify. I need help solving this how do u do this
2007-03-16 13:10:33 · 5 answers · asked by Yahoo! User 4 in Education & Reference ➔ Homework Help
There is no real solution to this problem. If you graph the equation, the parabola is entirely above the x-axis.
2007-03-16 13:22:25 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You will find the solution to that problem at the website below. Or one close to it.
Good Luck.
This one is close:
same problem just that it's -11 instead of plus, but I think you'll get the idea for this.
We can then continue on to use this technique to solve equations. Suppose we wanted to solve the equation
x2+6x-11=0.
Add 11 to both sides and this becomes
x2+6x=11.
Geometrically this says that the combined green and pink areas of my first example make 11. It's not so easy from that to see what x could be, but if we add 9 to both sides, adding the gold square to complete the square, we get
x2+6x+9=20,
which says that the area of the square of side length 3 more than x, the big square, must be 20,
(x+3)2=20,
the side length of the big square must be the square root of 20.
So x must be 3 less than that,
2007-03-16 20:19:27 · answer #2 · answered by Silly Girl 5 · 0⤊ 1⤋
Looking at this problem, you know you can't factor this equation out so your next solution would be to use the quadratic equation. The formula for the quadratic equation is -b plus or minus the square root of b^2 - 4(a)(c) all over 2a. The problem with using this formula is that you get a solution that is not real. When you set up the actual problem you end up getting:
-6 plus or minus the square root of 6^2 - 4(1)(11) all divided by (2)(1). The problem is that you cannot take the square root of a negative and in this case you would end up getting the negative square root of 8. There is no real solution to this problem.
2007-03-16 23:48:08 · answer #3 · answered by debbie_75052 4 · 1⤊ 0⤋
the problem is the problem
with 11 in the third slot - and a positive
the second number has to be +12 or a -12
as 11 has only 1,11 as factors
so you need to recheck your problem - or call a friend
and verify that you copied it off the board correctly
2007-03-16 20:16:05 · answer #4 · answered by tom4bucs 7 · 0⤊ 0⤋
there r 2 roots for the given general equation. they are {-6(+or -)18i}/4
2007-03-16 20:21:47 · answer #5 · answered by prem 2 · 0⤊ 0⤋