I don't think so either. Nash can make almost anybody in the NBA a better player - but Kobe ain't one of them.
Kobe likes to create his own shot, whether it's going to the rim of the jumper off the dribble. Nash's crafty passing would do Kobe no good. While Nash is unselfish and makes others better, he must IS the general of any offense in which he plays, and Kobe simply couldn't coexist with that.
In fairness to Kobe, Nash wouldn't make mesh well with Michael Jordan, either. Jordan, for some of the same reasons as Kobe, wasn't compatible with a traditional point guard.
Nash is like a God for big men and spot-up shooters. He adds a few points to all their averages.
2007-03-16 13:25:11
·
answer #1
·
answered by The Brain 3
·
0⤊
0⤋
No way. Kobe is a type of player that cant succeed if he has another superstar guard alongside him in the backcourt. He wants every play to run through him, wether its scoring or a passing play. im not saying kobe is a player who nobody likes to play with, its just that kobe is a player who will lead a team by himself and wont want any other guard or forward to help him. he compromised with shaq cuz they knew they can win a championship together. but look wat happened, they dissagreed in so many ways eventually, that shaq just demanded a trade. nash is a great player, and probably would want to play with kobe, but he knows that it will never happen. especially cuz wat happended last year in the playoffs.
2007-03-16 20:19:32
·
answer #2
·
answered by Majid K 2
·
0⤊
0⤋
Not sure, BUT, Go Steve Nash! Go Phoenix Suns! w00t!
2007-03-16 20:26:36
·
answer #3
·
answered by Anonymous
·
1⤊
0⤋
Yes
2007-03-16 20:29:24
·
answer #4
·
answered by messtograves 5
·
1⤊
0⤋
NO!!! Kobe would try to outshine Steve..he would bring up the ball, shooting, and rebounding for everybody...oh wait he does that now!
2007-03-16 23:13:17
·
answer #5
·
answered by hotgirl_rightgirl00 5
·
0⤊
0⤋
Maybe
2007-03-16 20:17:12
·
answer #6
·
answered by Nicole 5
·
0⤊
2⤋
no
2007-03-16 20:17:32
·
answer #7
·
answered by wolfwagon2002 5
·
0⤊
2⤋