An air filled spherical capacitor is constructed with inner and outer shell radii of 6.5 cm and 13.1 cm, respectively. The coulomb constant is 8.98755 X 10^9.
1. Calculate the capacitance of the device. Answer in units of pF.
2. In addition, what potential difference between the spheres results in a charge of 31.4 micro C on the capacitor? Answer in units of kV.
I tried using C= Q / Vab = 4πEo*(r_a*r_b / (r_b - r_a) but that didn't work.
2007-03-16 12:02:52 · 4 answers · asked by mcgrady111 1 in Science & Mathematics ➔ Physics
theres a good chance your equation is missing a constant. (Coulomb constant)
8.99x10^9 N m^2 / C^2
should be
4 pi E0(r_a*r_b) / (ke * (r_b - r_a)
2007-03-16 13:22:37 · answer #1 · answered by John 5 · 0⤊ 0⤋
1. C = eA/d with e : permitivity,; A is surface area,; d is distance b/t two plates
e(air) = 1 ( I guessed. Double check)
C1 = 4x Pix r1^2/(r2 - r1)
= 4x3.14x(6.5x10^-2)^2 / (6.6x10^-2) Farad
C2 = 4x3.14x(13.1x10^-2)^2 / (6.6x10^-2) Farad
Make sure convert to pF
1 Farad = 10 ^12 pF
2. Use C = Q/V
V = Q/C
find V1 and V2 and then take the difference. That is your final answer. Make sure convert to appropriate unit
Q = 31.4 microC = 31.4 x 10^-6 C
1 kV = 1000V
Good luck bloke!!!
2007-03-16 15:22:56 · answer #2 · answered by tuoidabuon 2 · 1⤊ 0⤋
the interpretation of the hebrew be conscious chuwg speaks of circumference and describes a good sphere. right it is yet another verse. interest 26:10 He has inscribed a circle on the outdoors of the waters on the boundary of sunshine and darkness. how can God shape a flat circle on the outdoors of water? the earth became void interior the commencing up and the Spirit of God hovered over the waters. the Bible has declared the earth is around.
2016-10-18 21:06:11 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Dude,
What's the prize??
That requires a lot of work..
2007-03-16 12:14:54 · answer #4 · answered by Anonymous · 0⤊ 1⤋