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A 11 pF capacitor is connected across a 71 V source. What charge is stored on it? Answer in Coulombs

2007-03-16 09:35:56 · 2 answers · asked by kpm0729 1 in Science & Mathematics Physics

2 answers

W=.5*C*(V^2) that is the energy stored in a capacitor.
change stored in capacitor = Q= C*V

2007-03-16 09:51:42 · answer #1 · answered by Anonymous · 0 0

Q = V*C = 71 * 1.1*10^-11 Coulombs.

2007-03-16 09:50:26 · answer #2 · answered by kirchwey 7 · 0 0

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