How many different rectangles can i draw with a perimeter of 3?

Answer 1

infinite number

Answer 2

Let this be known to you. Infinite might be the Answer but that is Theory.

In practise when the Angle can not be kept to a Perfect 90* then it is Not A Rectangle. Why you have not mentioned the Unit Value for 3 as Metre or Yard or inch.

When your drawing goes smaller and smaller then drawing it also will be difficult.

Incidentally A Square is also a Rectangle, but a Rectangle is Not a Square!

Answer 3

AS perimeter = 2(L+B) = 3
Therefore (L+B) =1.5
As there is no condition given for length and breadth the side will be lie between > 0 to = 1.5 i.e side >0 and = 1.5, 0 > x <= 1.5
In any numbers a and b there exists a middle number (a + b)/2
there will be infinite numbers having L and B with in the above limits with sum = 1.5 hence infinite number of rectangles can be drawn.

Answer 4

Be x the lenth and y the width of a rectangle, its perimeter p is 2(x + y)

If p=3 then x+y=1.5

x,y are both positive so

x and y are both in (0,1.5).

The number of values greater than 0 and smaller than 1.5 is infinity.

Answer 5

infinite number.
because a perimeter of 3 can be a combination of an infinite number of length and breadth of a rectangle.

for e.g
l=1.5, b= 0.5
l=1.4, b= 0.6
l=1.3, b=0.7, etc.

Answer 6

3 = 2l + 2w. There are infinitely many positive real pairs
that satisfy this equation

Answer 7

an infinite amount

1 by 1/2 by 1 by 1/2
1.01 by .49 by 1.01 by .49
1.001 by .499 etc etc

Answer 8

infinite....

i just wanted to say that lol

Answer 9

∞
infinity

Answer 10

infite