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Write an equation in standardform of the line that has the given slope and passes through the given point.

m=1 : (0,-1) and m=2 : (5,-1)

2007-03-16 05:28:19 · 8 answers · asked by Erynn C 1 in Science & Mathematics Mathematics

8 answers

You need to check your textbook for what they consider the "standard form".

Some say standard form is y = mx + b, which is what all the other people who answered you did.

However, some text books call that slope-intercept form and say standard form is Ax + By = C

-------------------

I'll use Ax + By = C

First use point-slope form to find the equation, then move it around into standard form.

for m = 1 and (0, -1)
y - (-1) = 1(x - 0)
y + 1 = x
-x + y = 1
or
x - y = -1

for m = 2 and (5, -1)
y - (-1) = 2(x - 5)
y + 1 = 2x - 10
-2x + y = -11
or
2x - y = 11

2007-03-16 05:53:08 · answer #1 · answered by Mathematica 7 · 0 0

In math, the slope of the line is symbolized by the letter m, and the equation for the standard form of the line may be written as y = mx + b.

Since you are given a point through which the line passes, you know that 0 and -1 are solutions to the standard equation, and you can substitute them in to solve for b, the y-intercept.

y = mx + b
-1 = 1(0) + b
-1 = b

Now you have the standard equation for the line in explicit form:

y = x - 1

Now, try this for your second slope and point.

2007-03-16 12:38:14 · answer #2 · answered by HallamFoe 4 · 0 0

The equation is of form y=mx + b

Given m, and the coordinates of the point, what you have to find is b:

m=1 (0, -1)

y = mx + b // put m=1,x=0,y=-1

-1=1*0 + b

-1=b

y=x-1

m=2; (5,-1)

-1=2*x + b

-1=10+b

b=-11

The equation is y=2x-11

2007-03-16 12:36:19 · answer #3 · answered by Amit Y 5 · 0 0

the standard for of writing an equation is y=mx+c, where m is the gradient and c is a constant.

to get this equation, we have to use another equation,
y-y1=m(x-x1)
or,
y-(-1)=1(x-0)
=>y+1=x
=>y=x-1 [y=mx+c]

and,
y-(-1)=2(x-5)
=>y+1=2x-10
=>y=2x-10-1
=>y=2x-11 [y=mx+c]

2007-03-16 12:38:40 · answer #4 · answered by Bubblez 3 · 0 0

Standard form of a line is y = mx+b, where y is the y coordinate, x is the x-coordinate, m is the slope, and b is the y-intercept.

2007-03-16 12:36:07 · answer #5 · answered by JOhn M 5 · 0 1

I see, and no, I'm sorry, I do not know what you mean. This question is like asking me how many stars flicker out and never come back on. Uh, are you working on your doctorate or master degree to become a scientist in the laws of physics and if you are, please, if you ask a question like about writing an equation in standardform, then, I'll have to take a back seat..one plus one equal two so they say, but one abstract with enough electronic mechanical tools to add up the approximate sum of how many atoms are in the number one, depending of course on how large these numbers look like, you know, like printed or in one dollar bills, then you will have to worry about using that electron microscope to count the abstract number to the sum of the atoms in the next one on one and one, so, what do you mean I don't know and I don't know the answer to how many abstract atoms are in the sum of one and one. Peace and tenderness and, please, have a peace of mind, you are so gifted in asking us, me too such extraordinary questions. You could have been Einsteins wife or girl friend with your kinds of questions.

2007-03-16 12:38:13 · answer #6 · answered by Pink Honey 3 · 0 3

y-(y coord given) = m (x - x coord given)

y-(-1) = 1(x-0)
y+1 = x

y=x-1

y-(-1) = 2(x-5)

y+1 = 2x -10

y=2x-11

2007-03-16 12:35:45 · answer #7 · answered by Maverick 7 · 0 0

y-y0=a(x-x0) <=> y=ax -ax0 +y0 <=> ax -y -ax0 +y0 =0,
where a is the slope and (x0, y0) is a point of that line

2007-03-16 12:38:30 · answer #8 · answered by supersonic332003 7 · 0 0

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